32-12x-5x^2=0

Solution for 32-12x-5x^2=0 equation:

32-12x-5x^2=0

a = -5; b = -12; c = +32;
Δ = b2-4ac
Δ = -122-4·(-5)·32
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-28}{2*-5}=\frac{-16}{-10}
=1+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+28}{2*-5}=\frac{40}{-10}
=-4
$